**Решение:**
a) $$\frac{7}{10} + \frac{2}{15} = \frac{7 \cdot 3}{10 \cdot 3} + \frac{2 \cdot 2}{15 \cdot 2} = \frac{21}{30} + \frac{4}{30} = \frac{21+4}{30} = \frac{25}{30} = \frac{5}{6}$$
б) $$\frac{3}{4} - \frac{5}{28} = \frac{3 \cdot 7}{4 \cdot 7} - \frac{5}{28} = \frac{21}{28} - \frac{5}{28} = \frac{21-5}{28} = \frac{16}{28} = \frac{4}{7}$$
в) $$\frac{6}{35} \cdot \frac{7}{24} = \frac{6 \cdot 7}{35 \cdot 24} = \frac{6 \cdot 7}{5 \cdot 7 \cdot 4 \cdot 6} = \frac{1}{5 \cdot 4} = \frac{1}{20}$$
г) $$\frac{10}{27} : \frac{25}{36} = \frac{10}{27} \cdot \frac{36}{25} = \frac{10 \cdot 36}{27 \cdot 25} = \frac{2 \cdot 5 \cdot 4 \cdot 9}{3 \cdot 9 \cdot 5 \cdot 5} = \frac{2 \cdot 4}{3 \cdot 5} = \frac{8}{15}$$
**Ответ:**
a) $$\frac{5}{6}$$; б) $$\frac{4}{7}$$; в) $$\frac{1}{20}$$; г) $$\frac{8}{15}$$