10. \(\frac{5x-7}{6x}-\frac{x-3}{6x}+\frac{2x-8}{6x}\)

\[\frac{5x-7}{6x}-\frac{x-3}{6x}+\frac{2x-8}{6x}=\frac{5x-7-x+3+2x-8}{6x}=\frac{6x-12}{6x}=\frac{x-2}{x}.\]

Ответ: \(\frac{x-2}{x}\).