Ответ:

  1. Поскольку \(3a-6=3(a-2)\), получаем \(\frac{3a-(3a+1)}{3(a-2)}=-\frac1{3(a-2)}\).
  2. \(\frac{18-6(b+3)}{b(b+3)}=-\frac6{b+3}\).
  3. \(\frac{2c-(c-1)}{c(c+1)}=\frac{c+1}{c(c+1)}=\frac1c\).
  4. \(\frac{d-1+2d}{2(d-4)}=\frac{3d-1}{2(d-4)}\).
  5. \(\frac{2(m+1)-3(m-1)}{6(m-5)}=\frac{5-m}{6(m-5)}\).
  6. \(\frac{2(m-2n)-3(m-3n)}{12(m+n)}=\frac{5n-m}{12(m+n)}\).
  7. \(\frac{2(a^2+2)-a(a+4)}{2a(a+2)}=\frac{2(1-a)}{a(a+2)}\).
  8. Разложим знаменатели: \(x^2-2xy=x(x-2y)\), \(xy-2y^2=y(x-2y)\). Тогда \(\frac{y(3x-4y)-x(3y-x)}{xy(x-2y)}=\frac{x^2-4y^2}{xy(x-2y)}=\frac{x+2y}{xy}\).