\( 1 \frac{1}{2} = \frac{1 × 2 + 1}{2} = \frac{3}{2} \)
\( \frac{1}{2} = \frac{1 × 4}{2 × 4} = \frac{4}{8} \)
\( \frac{3}{4} = \frac{3 × 2}{4 × 2} = \frac{6}{8} \)
\( \frac{3}{2} = \frac{3 × 4}{2 × 4} = \frac{12}{8} \)
\( \frac{7}{8} \) (без изменений)
\( \frac{3}{8} \) (без изменений)
\( \frac{3}{8} < \frac{4}{8} < \frac{6}{8} < \frac{7}{8} < \frac{12}{8} \)
\( 1 \frac{2}{3} = \frac{1 × 3 + 2}{3} = \frac{5}{3} \)
\( \frac{1}{3} = \frac{1 × 4}{3 × 4} = \frac{4}{12} \)
\( \frac{5}{3} = \frac{5 × 4}{3 × 4} = \frac{20}{12} \)
\( \frac{5}{6} = \frac{5 × 2}{6 × 2} = \frac{10}{12} \)
\( \frac{2}{3} = \frac{2 × 4}{3 × 4} = \frac{8}{12} \)
\( \frac{7}{12} \) (без изменений)
\( \frac{4}{12} < \frac{7}{12} < \frac{8}{12} < \frac{10}{12} < \frac{20}{12} \)
Ответ: а) \( \frac{3}{8}, \frac{1}{2}, \frac{3}{4}, \frac{7}{8}, 1 \frac{1}{2} \); б) \( \frac{1}{3}, \frac{7}{12}, \frac{2}{3}, \frac{5}{6}, 1 \frac{2}{3} \).