189. \(\left(2\frac{1}{3}+\frac{6}{7}\right)\div\frac{1}{3}-\frac{2}{9}=\)

\(2\frac{1}{3}=\frac{7}{3}\).

\(\left(\frac{7}{3}+\frac{6}{7}\right)\div\frac{1}{3}-\frac{2}{9}=\frac{67}{21}\cdot3-\frac{2}{9}=\frac{67}{7}-\frac{2}{9}=\frac{603-14}{63}=\frac{589}{63}=9\frac{22}{63}\).

Ответ: \(9\frac{22}{63}\).