Ответ:

  1. а) \(\sqrt{20}-\sqrt{125}+\sqrt{405}=2\sqrt{5}-5\sqrt{5}+9\sqrt{5}=6\sqrt{5}\).
  2. б) \(\sqrt{32}+\sqrt{200}-\sqrt{162}=4\sqrt{2}+10\sqrt{2}-9\sqrt{2}=5\sqrt{2}\).
  3. в) \(4\sqrt{27}-5\sqrt{48}+\frac14\sqrt{192}=4\cdot3\sqrt{3}-5\,4\sqrt{3}+\frac14\cdot8\sqrt{3}=12\sqrt{3}-20\sqrt{3}+2\sqrt{3}=-6\sqrt{3}\).
  4. г) \(3\sqrt{32}-5\sqrt{98}+\sqrt{242}=3\cdot4\sqrt{2}-5\cdot7\sqrt{2}+11\sqrt{2}=12\sqrt{2}-35\sqrt{2}+11\sqrt{2}=-12\sqrt{2}\).