Ответ:
- \(\dfrac{\sqrt3}{\sqrt{75}}+\sqrt{0.64}=\dfrac{\sqrt3}{5\sqrt3}+0.8=0.2+0.8=1\).
- \(\dfrac{\sqrt5}{\sqrt{125}}+\sqrt{0.0484}=\dfrac{\sqrt5}{5\sqrt5}+0.22=0.2+0.22=0.42\).
- \(\dfrac{\sqrt{27}}{\sqrt{96}}-\sqrt{256}=\dfrac{3\sqrt3}{4\sqrt6}-16=\dfrac{3\sqrt2}{8}-16\).
- \(-\dfrac{\sqrt{648}}{\sqrt{12}}+\sqrt{0.0081}=-\sqrt{54}+0.09=-3\sqrt6+0.09\).
Ответ: 1) \(1\); 2) \(0.42\); 3) \(\dfrac{3\sqrt2}{8}-16\); 4) \(0.09-3\sqrt6\).
