Ответ:
Первообразная: \(\frac{2x^3}{3}-x\).
\(\int_{1}^{2}(2x^2-1)\,dx=\left.\left(\frac{2x^3}{3}-x\right)\right|_{1}^{2}=\left(\frac{16}{3}-2\right)-\left(\frac{2}{3}-1\right)=\frac{10}{3}+\frac{1}{3}=\frac{11}{3}.\)
Ответ: \(\frac{11}{3}\).
Первообразная: \(\frac{2x^3}{3}-x\).
\(\int_{1}^{2}(2x^2-1)\,dx=\left.\left(\frac{2x^3}{3}-x\right)\right|_{1}^{2}=\left(\frac{16}{3}-2\right)-\left(\frac{2}{3}-1\right)=\frac{10}{3}+\frac{1}{3}=\frac{11}{3}.\)
Ответ: \(\frac{11}{3}\).