39) \(\frac{27}{28}\) \(\cdot\) \(\frac{49}{45}\) =

Решение:

\( \frac{27}{28} \cdot \frac{49}{45} = \frac{27 \cdot 49}{28 \cdot 45} \)

Сократим 27 и 45 на 9:

\( 27 \div 9 = 3 \)

\( 45 \div 9 = 5 \)

Сократим 49 и 28 на 7:

\( 49 \div 7 = 7 \)

\( 28 \div 7 = 4 \)

\( \frac{3 \cdot 7}{4 \cdot 5} = \frac{21}{20} = 1 \frac{1}{20} \)

Ответ: 1 \(\frac{1}{20}\)