41.4. \(2\frac{12}{17}\cdot\left(1\frac{10}{15}-\frac{4}{12}:7\right)-3\frac{3}{18}\)

Упростим дроби: \(2\frac{12}{17}=\frac{46}{17}\), \(1\frac{10}{15}=\frac{5}{3}\), \(\frac{4}{12}=\frac{1}{3}\), \(3\frac{3}{18}=\frac{7}{2}\).

\(\frac{1}{3}:7=\frac{1}{21}\), поэтому \(\frac{5}{3}-\frac{1}{21}=\frac{35-1}{21}=\frac{34}{21}\).

\(\frac{46}{17}\cdot\frac{34}{21}-\frac{7}{2}=\frac{1564}{357}-\frac{7}{2}=\frac{3128-2499}{714}=\frac{629}{714}\).

Ответ: \(\frac{629}{714}\).