Ответ:
Используем правило: \(a^{-n}=\frac{1}{a^n}\).
- \(12^{-2}=\frac{1}{12^2}=\frac{1}{144}\).
- \(3^{-4}=\frac{1}{3^4}=\frac{1}{81}\).
- \((-2)^{-6}=\frac{1}{(-2)^6}=\frac{1}{64}\).
- \((-5)^{-3}=\frac{1}{(-5)^3}=-\frac{1}{125}\).
- \(\left(-\frac{1}{8}\right)^{-1}=-8\).
- \(\left(\frac{2}{3}\right)^{-3}=\left(\frac{3}{2}\right)^3=\frac{27}{8}\).
- \(\left(-\frac{7}{9}\right)^{-2}=\left(-\frac{9}{7}\right)^2=\frac{81}{49}\).
- \(\left(1\frac{2}{3}\right)^{-1}=\left(\frac{5}{3}\right)^{-1}=\frac{3}{5}\).
- \(0{,}3^{-2}=\left(\frac{3}{10}\right)^{-2}=\frac{100}{9}\).
- \(1{,}6^{-2}=\left(\frac{8}{5}\right)^{-2}=\frac{25}{64}\).
