Ответ:\(\sqrt[5]{3^{-2}}=3^{-2/5}=\frac{1}{\sqrt[5]{9}}\).\(\sqrt[6]{8^{-5}}=8^{-5/6}=2^{-15/6}=2^{-5/2}=\frac{\sqrt2}{8}\).\(\sqrt[4]{0{,}2^{-8}}=0{,}2^{-2}=25\).\(\sqrt[5]{\left(\frac12\right)^{-10}}=2^2=4\).