Ответ:\((n+3)!/(n+1)!=(n+3)(n+2)\).\((n+2)!/(n-1)!=n(n+1)(n+2)\).\((1/(n+1)!+1/n!)n!=1/(n+1)+1=(n+2)/(n+1)\).\((1/n!-1/(n+1)!)n!=1-1/(n+1)=n/(n+1)\).\((1/n!-1/(n+2)!)(n+1)!=n+1-1/(n+2)\).\((1/(n+2)!+1/n!)(n+1)!=(n+1)+1/(n+2)\).