Ответ:\(x^2-10x+10=(x-5)^2-15\).\(x^2+3x-1=\left(x+\frac32\right)^2-\frac{13}{4}\).\(3x^2+6x-3=3(x^2+2x-1)=3(x+1)^2-6\).\(\frac14x^2-x+2=\frac14(x^2-4x+8)=\frac14(x-2)^2+1\).