Ответ:
\(21^0=1\), \(3^{-2}=\frac19\), \(4^{-2}=\frac1{16}\):
\(1-\frac19-\frac1{16}=1-\frac{16}{144}-\frac9{144}=\frac{119}{144}\).
\(2^{-3}=\frac18\), \(3^{-1}=\frac13\), \((-4)^2=16\):
\(\frac18+\frac13+16=\frac3{24}+\frac8{24}+\frac{384}{24}=\frac{395}{24}\).
\(9^{-1}=\frac19\), ал \(\frac{(-3)^2}{(-5)^2}=\frac9{25}\):
\(\frac19-\frac9{25}=\frac{25-81}{225}=-\frac{56}{225}\).
Жауабы: 1) \(\frac{119}{144}\); 2) \(\frac{395}{24}\); 3) \(-\frac{56}{225}\).
