Ответ:\(\frac{a^8a^{-7}}{a^{-2}}=a^{8-7-(-2)}=a^3\). При \(a=0{,}8\): \(0{,}8^3=0{,}512\).\(\frac{a^{15}a^3}{a^{13}}=a^{15+3-13}=a^5\). При \(a=\frac12\): \(\left(\frac12\right)^5=\frac1{32}\).