2) $$\frac{40a^5b^9}{39c^6d^{14}} : \left(-\frac{5a^8b^3}{26c^{12}d^7}\right) = \frac{40a^5b^9}{39c^6d^{14}} \cdot \left(-\frac{26c^{12}d^7}{5a^8b^3}\right) = -\frac{40a^5b^9 \cdot 26c^{12}d^7}{39c^6d^{14} \cdot 5a^8b^3} = -\frac{8a^5b^9 \cdot 2c^{12}d^7}{3c^6d^{14} \cdot a^8b^3} = -\frac{16c^{12-6}b^{9-3}}{3a^{8-5}d^{14-7}} = -\frac{16c^6b^6}{3a^3d^7}$$
Ответ: -16b⁶c⁶/(3a³d⁷)