2) 3xy-y²/xy+2y² * x²y+2xy²/3x³-x²y;

2) $$\frac{3xy - y^2}{xy + 2y^2} \cdot \frac{x^2y + 2xy^2}{3x^3 - x^2y} = \frac{y(3x-y)}{y(x+2y)} \cdot \frac{xy(x+2y)}{x^2(3x-y)} = \frac{y(3x-y)xy(x+2y)}{y(x+2y)x^2(3x-y)} = \frac{xy}{x^2} = \frac{y}{x}$$

Ответ: y/x