a) (4√3+3√2)(√27-√2);

a) Упростим выражение:

$$ (4\sqrt{3} + 3\sqrt{2})(\sqrt{27} - \sqrt{2}) = (4\sqrt{3} + 3\sqrt{2})(3\sqrt{3} - \sqrt{2}) = $$

$$ = 4\sqrt{3} \cdot 3\sqrt{3} - 4\sqrt{3} \cdot \sqrt{2} + 3\sqrt{2} \cdot 3\sqrt{3} - 3\sqrt{2} \cdot \sqrt{2} = $$

$$ = 12 \cdot 3 - 4\sqrt{6} + 9\sqrt{6} - 3 \cdot 2 = 36 - 6 + 5\sqrt{6} = 30 + 5\sqrt{6}$$

Ответ: $$30 + 5\sqrt{6}$$