б) (1/3 √6+√2)(√2-1/3 √6);

б) Упростим выражение:

$$(\frac{1}{3}\sqrt{6} + \sqrt{2})(\sqrt{2} - \frac{1}{3}\sqrt{6}) = (\sqrt{2} + \frac{1}{3}\sqrt{6})(\sqrt{2} - \frac{1}{3}\sqrt{6}) =$$

$$ = (\sqrt{2})^2 - (\frac{1}{3}\sqrt{6})^2 = 2 - \frac{1}{9} \cdot 6 = 2 - \frac{2}{3} = \frac{6}{3} - \frac{2}{3} = \frac{4}{3} = 1\frac{1}{3}$$

Ответ: $$1\frac{1}{3}$$