C.2.33. Решить уравнение: 1) (10+5x)/(x-4) = 1/2; 2) (2x-16)/(x+1) = -1 1/3.

1) \(\frac{10 + 5x}{x - 4} = \frac{1}{2}\) \(2(10 + 5x) = 1(x - 4)\) \(20 + 10x = x - 4\) \(10x - x = -4 - 20\) \(9x = -24\) \(x = -\frac{24}{9} = -\frac{8}{3}\) 2) \(\frac{2x - 16}{x + 1} = -1\frac{1}{3} = -\frac{4}{3}\) \(3(2x - 16) = -4(x + 1)\) \(6x - 48 = -4x - 4\) \(6x + 4x = -4 + 48\) \(10x = 44\) \(x = \frac{44}{10} = \frac{22}{5} = 4,4\)