Е, 10) b/(x−y)³ + 10/[3(x−y)²] =

Общий знаменатель — \(3(x-y)^3\): \(\frac{b}{(x-y)^3}+\frac{10}{3(x-y)^2}=\frac{3b+10(x-y)}{3(x-y)^3}\).

Ответ: \(\frac{3b+10(x-y)}{3(x-y)^3}\).