$\frac{b}{(x-y)^3}+\frac{10}{3(x-y)^2}=$

Question

Вопрос: $Фото задания: $\frac{b}{(x-y)^3}+\frac{10}{3(x-y)^2}=$$ Фото задания

Accepted Answer

Общий знаменатель — $3(x-y)^3$:

\[\frac{3b}{3(x-y)^3}+\frac{10(x-y)}{3(x-y)^3}=\frac{3b+10(x-y)}{3(x-y)^3}.\]

Ответ: $\frac{3b+10(x-y)}{3(x-y)^3}$.

\(\frac{b}{(x-y)^3}+\frac{10}{3(x-y)^2}=\)