04.35. г) n/(m^2+2mn) + (m-2n)/(4mn)

г) $$ \frac{n}{m^2+2mn} + \frac{m-2n}{4mn} = \frac{n}{m(m+2n)} + \frac{m-2n}{4mn} = \frac{4n^2 + (m-2n)(m+2n)}{4mn(m+2n)} = \frac{4n^2 + m^2 - 4n^2}{4mn(m+2n)} = \frac{m^2}{4mn(m+2n)} = \frac{m}{4n(m+2n)} $$

Ответ: $$ \frac{m}{4n(m+2n)} $$