г) $$ \frac{x+y}{3(x-y)} + \frac{x^2}{(x-y)^2} = \frac{(x+y)(x-y) + 3x^2}{3(x-y)^2} = \frac{x^2 - y^2 + 3x^2}{3(x-y)^2} = \frac{4x^2 - y^2}{3(x-y)^2} $$
Ответ: $$ \frac{4x^2 - y^2}{3(x-y)^2} $$