Рассмотрим два случая:
\[ \frac{1}{3}x - 5 = 6 \]
\[ \frac{1}{3}x = 6 + 5 \]
\[ \frac{1}{3}x = 11 \]
\[ x = 11 \cdot 3 \]
\[ x = 33 \]
\[ \frac{1}{3}x - 5 = -6 \]
\[ \frac{1}{3}x = -6 + 5 \]
\[ \frac{1}{3}x = -1 \]
\[ x = -1 \cdot 3 \]
\[ x = -3 \]
Ответ: x = 33, x = -3