2 9. log 644 log√3 27

9. $$ \frac{2}{3}log_4 64 + 4log_{\sqrt{3}} 27 = \frac{2}{3}log_4 4^3 + 4 log_{3^{1/2}} 3^3 = \frac{2}{3} \cdot 3 log_4 4 + 4 \cdot 3 log_{3^{1/2}} 3 = 2 \cdot 1 + 12 log_{3^{1/2}} 3 $$.

$$log_{3^{1/2}} 3 = log_{3^{1/2}} (3^{1/2})^2 = 2log_{3^{1/2}} 3^{1/2} = 2 \cdot 1 = 2$$.

$$2 + 12 \cdot 2 = 2 + 24 = 26$$.

Ответ: 26