5.301 Найдите сумму: 7 a) 6+8; 13 5 6) 12+19; 24 7 в) 5+8; 15 5 г) 13+7; 101 7 д) 4+15; 7 9 e) 3+4;

a) $$6\frac{7}{13} + 8\frac{7}{13} = (6+8) + \frac{7+7}{13} = 14 + \frac{14}{13} = 14 + 1\frac{1}{13} = 15\frac{1}{13}$$

б) $$12\frac{5}{24} + 19\frac{5}{24} = (12+19) + \frac{5+5}{24} = 31 + \frac{10}{24} = 31 + \frac{5}{12} = 31\frac{5}{12}$$

в) $$5\frac{7}{15} + 8\frac{4}{15} = (5+8) + \frac{7+4}{15} = 13 + \frac{11}{15} = 13\frac{11}{15}$$

г) $$13\frac{5}{101} + 7\frac{25}{101} = (13+7) + \frac{5+25}{101} = 20 + \frac{30}{101} = 20\frac{30}{101}$$

д) $$4\frac{7}{7} + 15\frac{7}{7} = (4+15) + \frac{7+7}{7} = 19 + \frac{14}{7} = 19 + 2 = 21$$

e) $$3\frac{9}{13} + 4\frac{8}{13} = (3+4) + \frac{9+8}{13} = 7 + \frac{17}{13} = 7 + 1\frac{4}{13} = 8\frac{4}{13}$$

Ответ: a) $$15\frac{1}{13}$$, б) $$31\frac{5}{12}$$, в) $$13\frac{11}{15}$$, г) $$20\frac{30}{101}$$, д) 21, e) $$8\frac{4}{13}$$