a) {-2 < 3x-5 < 19, 3x - 1 < 5, 3x-5 > x + 7
$$-2 < 3x-5 < 19$$
$$3 < 3x < 24$$
$$1 < x < 8$$
$$3x - 1 < 5$$
$$3x < 6$$
$$x < 2$$
$$3x-5 > x + 7$$
$$2x > 12$$
$$x > 6$$
Решение: $$(1 < x < 8) \cap (x < 2) \cap (x > 6) => (6 < x < 2) => \emptyset $$
б) {-3 < 2x-1 < 7, 3x + 2 < x, 2x - 1 ≥ x + 2
$$-3 < 2x-1 < 7$$
$$-2 < 2x < 8$$
$$-1 < x < 4$$
$$3x + 2 < x$$
$$2x < -2$$
$$x < -1$$
$$2x - 1 ≥ x + 2$$
$$x ≥ 3$$
Решение: $$(-1 < x < 4) \cap (x < -1) \cap (x ≥ 3) => \emptyset $$
в) {1 < 2x-1 < 5, 2 ≤ 3x-1 < 11, {10 ≤ 4x-2 < 26, 3 < 2x-1 < 11.
{1 < 2x-1 < 5
$$2 < 2x < 6$$
$$1 < x < 3$$
{2 ≤ 3x-1 < 11
$$3 ≤ 3x < 12$$
$$1 ≤ x < 4$$
Решение: $$(1 < x < 3) \cap (1 ≤ x < 4) => (1 < x < 3)$$
{10 ≤ 4x-2 < 26
$$12 ≤ 4x < 28$$
$$3 ≤ x < 7$$
{3 < 2x-1 < 11
$$4 < 2x < 12$$
$$2 < x < 6$$
Решение: $$(3 ≤ x < 7) \cap (2 < x < 6) => (3 ≤ x < 6)$$
Итоговое решение: $$(1 < x < 3) \cap (3 ≤ x < 6) => \emptyset $$