1) \(5^{-2} + (\frac{10}{3})^{-1} = \frac{1}{5^2} + \frac{3}{10} = \frac{1}{25} + \frac{3}{10} = \frac{2}{50} + \frac{15}{50} = \frac{17}{50} = 0.34\)
2) \(\frac{17^{-7} \cdot 17^{-9}}{17^{-15}} = \frac{17^{-7-9}}{17^{-15}} = \frac{17^{-16}}{17^{-15}} = 17^{-16-(-15)} = 17^{-16+15} = 17^{-1} = \frac{1}{17}\)