Найдите значение выражения а) 3sin \frac{\pi}{6} +5 cos \frac{\pi}{3}; б) tg \frac{\pi}{3} - sin \frac{\pi}{3} - cos \frac{\pi}{6}

Ответ: а) 4; б) 0

а)

3sin \(\frac{\pi}{6}\) + 5cos \(\frac{\pi}{3}\) = 3 \(\cdot\) \(\frac{1}{2}\) + 5 \(\cdot\) \(\frac{1}{2}\) = \(\frac{3}{2}\) + \(\frac{5}{2}\) = \(\frac{8}{2}\) = 4

б)

tg \(\frac{\pi}{3}\) - sin \(\frac{\pi}{3}\) - cos \(\frac{\pi}{6}\) = \(\sqrt{3}\) - \(\frac{\sqrt{3}}{2}\) - \(\frac{\sqrt{3}}{2}\) = \(\sqrt{3}\) - \(\sqrt{3}\) = 0

Ответ: а) 4; б) 0