a) $$2x + \frac{1}{4}y$$ при $$x = 2\frac{1}{4}, y = 9$$:
$$2 \cdot 2\frac{1}{4} + \frac{1}{4} \cdot 9 = 2 \cdot \frac{9}{4} + \frac{9}{4} = \frac{18}{4} + \frac{9}{4} = \frac{27}{4} = 6\frac{3}{4}$$.
б) $$2\frac{3}{4}x - 1\frac{2}{11}y$$ при $$x = 1\frac{1}{5}, y = 1\frac{2}{3}$$:
$$2\frac{3}{4} \cdot 1\frac{1}{5} - 1\frac{2}{11} \cdot 1\frac{2}{3} = \frac{11}{4} \cdot \frac{6}{5} - \frac{13}{11} \cdot \frac{5}{3} = \frac{66}{20} - \frac{65}{33} = \frac{33 \cdot 66 - 20 \cdot 65}{20 \cdot 33} = \frac{2178 - 1300}{660} = \frac{878}{660} = \frac{439}{330} = 1\frac{109}{330}$$.
Ответ: а) $$6\frac{3}{4}$$; б) $$1\frac{109}{330}$$.