в) \(\frac{(2^5)^2}{2^6 \cdot 4} = \frac{2^{5 \cdot 2}}{2^6 \cdot 2^2} = \frac{2^{10}}{2^{6+2}} = \frac{2^{10}}{2^8} = 2^{10-8} = 2^2 = 4\)
г) \(\frac{3^7 \cdot 27}{(3^4)^3} = \frac{3^7 \cdot 3^3}{3^{4 \cdot 3}} = \frac{3^{7+3}}{3^{12}} = \frac{3^{10}}{3^{12}} = 3^{10-12} = 3^{-2} = \frac{1}{3^2} = \frac{1}{9}\)