2. Найдите значение выражения n²-6n +9 +(9-n)(n + 9) при п = -\frac{1}{6}.

Выполним задание:

Подставим значение n = -\(\frac{1}{6}\) в выражение n² - 6n + 9 + (9 - n)(n + 9):

(- \(\frac{1}{6}\))² - 6 \(\cdot\) (- \(\frac{1}{6}\)) + 9 + (9 - (- \(\frac{1}{6}\)))(- \(\frac{1}{6}\) + 9) = \(\frac{1}{36}\) + 1 + 9 + (9 + \(\frac{1}{6}\))(9 - \(\frac{1}{6}\)) = \(\frac{1}{36}\) + 10 + (\(\frac{54}{6}\) + \(\frac{1}{6}\))( \(\frac{54}{6}\) - \(\frac{1}{6}\)) = \(\frac{1}{36}\) + 10 + \(\frac{55}{6}\) \(\cdot\) \(\frac{53}{6}\) = \(\frac{1}{36}\) + 10 + \(\frac{2915}{36}\) = \(\frac{1}{36}\) + \(\frac{360}{36}\) + \(\frac{2915}{36}\) = \(\frac{3276}{36}\) = 91

Ответ: 91