$$y^2 - \frac{9y-2}{7} = 0$$
$$7y^2 - 9y + 2 = 0$$
$$D = (-9)^2 - 4 \cdot 7 \cdot 2 = 81 - 56 = 25$$
$$y_1 = \frac{-(-9) + \sqrt{25}}{2 \cdot 7} = \frac{9 + 5}{14} = \frac{14}{14} = 1$$
$$y_2 = \frac{-(-9) - \sqrt{25}}{2 \cdot 7} = \frac{9 - 5}{14} = \frac{4}{14} = \frac{2}{7}$$
Ответ: y₁ = 1, y₂ = 2/7