а) −11x³y⁴ ⋅ 0,3x²y³ = −11 ⋅ 0,3 ⋅ x³ ⋅ x² ⋅ y⁴ ⋅ y³ = -3,3x⁵y⁷
б) a³b ⋅ (−ab²c) = -1 ⋅ a³ ⋅ a ⋅ b ⋅ b² ⋅ c = -a⁴b³c
в) 4xy ⋅ (−x²) ⋅ (−y³) = 4 ⋅ (−1) ⋅ (−1) ⋅ x ⋅ x² ⋅ y ⋅ y³ = 4x³y⁴
г) a²x³b ⋅ (−0,6axb²) ⋅ 0,6a²b³ = -0,6 ⋅ 0,6 ⋅ a² ⋅ a ⋅ a² ⋅ x³ ⋅ x ⋅ b ⋅ b² ⋅ b³ = -0,216a⁵x⁴b⁶
Ответ: а) -3,3x⁵y⁷; б) -a⁴b³c; в) 4x³y⁴; г) -0,216a⁵x⁴b⁶