a) (a + 1)(a – 2)(a + 3) = (a² - 2a + a - 2)(a + 3) = (a² - a - 2)(a + 3) = a³ + 3a² - a² - 3a - 2a - 6 = a³ + 2a² - 5a - 6
б) (x – 2)(x – 3)(x + 4) = (x² - 3x - 2x + 6)(x + 4) = (x² - 5x + 6)(x + 4) = x³ + 4x² - 5x² - 20x + 6x + 24 = x³ - x² - 14x + 24
Ответ: a³ + 2a² - 5a - 6; x³ - x² - 14x + 24