4. Реши уравнение:$$\frac{8y-2}{1\frac{2}{3}} = \frac{3y + 1}{0.8}$$

$$\frac{8y-2}{1\frac{2}{3}} = \frac{3y + 1}{0.8}$$

$$\frac{8y-2}{\frac{5}{3}} = \frac{3y + 1}{\frac{4}{5}}$$

$$\frac{3(8y-2)}{5} = \frac{5(3y + 1)}{4}$$

$$\frac{24y-6}{5} = \frac{15y + 5}{4}$$

$$4(24y-6) = 5(15y + 5)$$

$$96y - 24 = 75y + 25$$

$$21y = 49$$

$$y = \frac{49}{21}$$

$$y = \frac{7}{3}$$

$$y = 2\frac{1}{3}$$

Ответ: $$y = 2\frac{1}{3}$$.