Решить уравнение (26—27).

26. Решить уравнение:

1. 1) (1-6i) + z = -4-7i
   \[ z = (-4-7i) - (1-6i) \]
   \[ z = -4 - 7i - 1 + 6i \]
   \[ z = -5 - i \]
2. 2) (2√5-3√3i) - z = √5+√3i
   \[ z = (2√5-3√3i) - (√5+√3i) \]
   \[ z = 2√5 - 3√3i - √5 - √3i \]
   \[ z = √5 - 4√3i \]
3. 3) (5-4i) - z = 3-5i
   \[ z = (5-4i) - (3-5i) \]
   \[ z = 5 - 4i - 3 + 5i \]
   \[ z = 2 + i \]
4. 4) z + (5-√2)i = 6-i
   \[ z = (6-i) - (5-√2)i \]
   \[ z = 6 - i - 5i + √2i \]
   \[ z = 6 + (-1-5+√2)i \]
   \[ z = 6 + (-6+√2)i \]

27. Решить уравнение:

1. 1) z(3-2i) = 1+2i
   \[ z = \frac{1+2i}{3-2i} = \frac{(1+2i)(3+2i)}{(3-2i)(3+2i)} = \frac{3 + 2i + 6i + 4i^2}{9 - 4i^2} = \frac{3 + 8i - 4}{9 + 4} = \frac{-1 + 8i}{13} = -\frac{1}{13} + \frac{8}{13}i \]
2. 2) z(-3+2i) = 5-4i
   \[ z = \frac{5-4i}{-3+2i} = \frac{(5-4i)(-3-2i)}{(-3+2i)(-3-2i)} = \frac{-15 - 10i + 12i + 8i^2}{9 - 4i^2} = \frac{-15 + 2i - 8}{9 + 4} = \frac{-23 + 2i}{13} = -\frac{23}{13} + \frac{2}{13}i \]
3. 3) z(1-3i) - 6 = 2i
   \[ z(1-3i) = 6 + 2i \]
   \[ z = \frac{6+2i}{1-3i} = \frac{(6+2i)(1+3i)}{(1-3i)(1+3i)} = \frac{6 + 18i + 2i + 6i^2}{1 - 9i^2} = \frac{6 + 20i - 6}{1 + 9} = \frac{20i}{10} = 2i \]
4. 4) z(-1+i) - 7i = -1
   \[ z(-1+i) = -1 + 7i \]
   \[ z = \frac{-1+7i}{-1+i} = \frac{(-1+7i)(-1-i)}{(-1+i)(-1-i)} = \frac{1 + i - 7i - 7i^2}{1 - i^2} = \frac{1 - 6i + 7}{1 + 1} = \frac{8 - 6i}{2} = 4 - 3i \]