Сократите дробь (16a²-8a+1)/(1-4a+x-4ax).

\(\frac{16a^2-8a+1}{1-4a+x-4ax}\) = \(\frac{(4a-1)^2}{1-4a+x(1-4a)}\) = \(\frac{(4a-1)^2}{(1-4a)(1+x)}\) = \(\frac{(4a-1)^2}{-(4a-1)(1+x)}\) = \(\frac{4a-1}{-(1+x)}\) = \(\frac{1-4a}{1+x}\).