\(\frac{2x+3}{(x-3)^2}\) \(\cdot\) \(\frac{(3-x)(3+x)}{(2x-3)(2x+3)}\) + \(\frac{1}{2x-3}\) \(\cdot\) \(\frac{1}{2(x-3)}\) = \(\frac{-(x-3)}{(x-3)^2}\) + \(\frac{1}{2(2x-3)(x-3)}\) = \(\frac{-1}{x-3}\) + \(\frac{1}{2(2x-3)(x-3)}\) = \(\frac{-2(2x-3) + 1}{2(2x-3)(x-3)}\) = \(\frac{-4x+6+1}{2(2x-3)(x-3)}\) = \(\frac{-4x+7}{2(2x-3)(x-3)}\).