Сократите дробь: 1) (x-25)/(√x-5); 2) (6+5√6)/√6; 3) (c+14√c+49)/(c-49).

\(\frac{x-25}{\sqrt{x}-5}\)

\(\frac{(\sqrt{x}-5)(\sqrt{x}+5)}{\sqrt{x}-5} = \sqrt{x} + 5\)

Ответ: \(\sqrt{x} + 5\)

\(\frac{6+5\sqrt{6}}{\sqrt{6}}\)

\(\frac{6+5\sqrt{6}}{\sqrt{6}} = \frac{6}{\sqrt{6}} + \frac{5\sqrt{6}}{\sqrt{6}} = \frac{6\sqrt{6}}{6} + 5 = \sqrt{6} + 5\)

Ответ: \(\sqrt{6} + 5\)

\(\frac{c + 14\sqrt{c} + 49}{c-49}\)

\(\frac{(\sqrt{c} + 7)^2}{(\sqrt{c} - 7)(\sqrt{c} + 7)} = \frac{\sqrt{c} + 7}{\sqrt{c} - 7}\)

Ответ: \(\frac{\sqrt{c} + 7}{\sqrt{c} - 7}\)