$$p - \frac{3}{11}p + 2 \frac{15}{22}p$$
$$p - \frac{6}{22}p + 2 \frac{15}{22}p = (1 - \frac{6}{22} + 2 \frac{15}{22})p = (\frac{22}{22} - \frac{6}{22} + 2 \frac{15}{22})p = (\frac{16}{22} + 2 \frac{15}{22})p = 2 \frac{31}{22}p = 3 \frac{9}{22}p = \frac{75}{22}p$$
При $$p = 1 \frac{19}{25} = \frac{44}{25}$$
$$\frac{75}{22} \cdot \frac{44}{25} = \frac{75 \cdot 44}{22 \cdot 25} = \frac{3 \cdot 25 \cdot 2 \cdot 22}{22 \cdot 25} = 3 \cdot 2 = 6$$
Ответ: 6