$$3 \frac{6}{7}b - b + 2 \frac{1}{14}b$$
$$3 \frac{12}{14}b - b + 2 \frac{1}{14}b = (3 \frac{12}{14} - 1 + 2 \frac{1}{14})b = (2 \frac{12}{14} + 2 \frac{1}{14})b = (4 \frac{13}{14})b = \frac{69}{14}b$$
При $$b = 9 \frac{1}{3} = \frac{28}{3}$$
$$\frac{69}{14} \cdot \frac{28}{3} = \frac{69 \cdot 28}{14 \cdot 3} = \frac{69 \cdot 2}{3} = 23 \cdot 2 = 46$$
Ответ: 46