Сначала упростим дроби:
a) \(\frac{8}{240}\) = \(\frac{1}{30}\) \(\approx\) 0.033
б) \(\frac{12}{16}\) = \(\frac{3}{4}\) = 0.75
в) \(\frac{6}{24}\) = \(\frac{1}{4}\) = 0.25
г) \(\frac{34-12}{4 \cdot 17}\) = \(\frac{22}{68}\) = \(\frac{11}{34}\) \(\approx\) 0.32
Теперь запишем их в порядке убывания:
\(\frac{12}{16}\), \(\frac{34-12}{4 \cdot 17}\), \(\frac{6}{24}\), \(\frac{8}{240}\)