Сначала упростим дроби:
a) \(\frac{90}{450}\) = \(\frac{1}{5}\) = 0.2
б) \(\frac{6}{16}\) = \(\frac{3}{8}\) = 0.375
в) \(\frac{8}{88}\) = \(\frac{1}{11}\) \(\approx\) 0.09
г) \(\frac{36-14}{7 \cdot 12}\) = \(\frac{22}{84}\) = \(\frac{11}{42}\) \(\approx\) 0.26
Теперь запишем их в порядке убывания:
\(\frac{6}{16}\), \(\frac{36-14}{7 \cdot 12}\), \(\frac{90}{450}\), \(\frac{8}{88}\)