Сначала упростим дроби:
a) \(\frac{90}{630}\) = \(\frac{1}{7}\) \(\approx\) 0.14
б) \(\frac{8}{14}\) = \(\frac{4}{7}\) \(\approx\) 0.57
в) \(\frac{3}{27}\) = \(\frac{1}{9}\) \(\approx\) 0.11
г) \(\frac{34 \cdot 12}{3 \cdot 17}\) = \(\frac{2 \cdot 12}{3}\) = \(\frac{24}{3}\) = 8
Теперь запишем их в порядке возрастания:
\(\frac{3}{27}\), \(\frac{90}{630}\), \(\frac{8}{14}\), \(\frac{34 \cdot 12}{3 \cdot 17}\)