а) \(\frac{5}{6} + \frac{3}{8} = \frac{5 \cdot 4}{6 \cdot 4} + \frac{3 \cdot 3}{8 \cdot 3} = \frac{20}{24} + \frac{9}{24} = \frac{20+9}{24} = \frac{29}{24}\)
б) \(\frac{2}{3} - \frac{5}{18} = \frac{2 \cdot 6}{3 \cdot 6} - \frac{5}{18} = \frac{12}{18} - \frac{5}{18} = \frac{12-5}{18} = \frac{7}{18}\)
в) \(\frac{5}{6} - \frac{2}{9} + \frac{1}{15} = \frac{5 \cdot 15}{6 \cdot 15} - \frac{2 \cdot 10}{9 \cdot 10} + \frac{1 \cdot 6}{15 \cdot 6} = \frac{75}{90} - \frac{20}{90} + \frac{6}{90} = \frac{75-20+6}{90} = \frac{61}{90}\)
Ответ: а) \(\frac{29}{24}\), б) \(\frac{7}{18}\), в) \(\frac{61}{90}\)