Ответ:

  1. а) \(\left(1\frac{1}{2}\right)^3-2\frac{1}{3}\cdot1\frac{1}{4}=\frac{27}{8}-\frac{35}{12}=\frac{81-70}{24}=\frac{11}{24}\).
  2. б) \(\frac{4}{9}\left(3\frac{3}{14}\cdot2\frac{4}{5}\right)^2=\frac{4}{9}\left(\frac{45}{14}\cdot\frac{14}{5}\right)^2=\frac{4}{9}\cdot9^2=36\).
  3. в) \(\left(\left(\frac{2}{3}\right)^3+\frac{5}{9}\right)\cdot\frac{9}{11}=\left(\frac{8}{27}+\frac{15}{27}\right)\cdot\frac{9}{11}=\frac{23}{33}\).
  4. г) \(\left(2\frac{1}{2}-\frac{11}{14}\right)\left(1\frac{4}{9}+2\frac{5}{6}-2\frac{3}{4}\right)=\frac{12}{7}\cdot\frac{55}{36}=\frac{55}{21}=2\frac{13}{21}\).

Ответ: а) 11/24; б) 36; в) 23/33; г) 2 13/21.