Вычислите: a) sin300°; б) tg(-2π/3); в) 2sin(π/3) - cos(π/2)

a) sin300° = sin(360° - 60°) = -sin60° = -√3/2

б) tg(-2π/3) = tg(-120°) = tg(-120° + 180°) = tg(60°) = √3

в) 2sin(π/3) - cos(π/2) = 2 * (√3/2) - 0 = √3

Ответ: a) -√3/2; б) √3; в) √3